Computer Networking Tutorial – 26 – Network IP Address

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21 responses to “Computer Networking Tutorial – 26 – Network IP Address”

  1. Marquis Chan Avatar

    Is the correct usable IP range from 19.244.47.9719.244.47.126?

  2. nadina yasmin Avatar

    I wanted to thank you very much for your videos, I'm just approaching this subject that seems so complex but thank to you now I learned some stuff. Appreciate your work!

  3. Alf Atlant Avatar

    ip: 19.244.47.96 and 23 usable hosts

  4. Supun Sandusha Avatar

    thanks for the video .. network ip : 19 :244:47:96

  5. Archit Singh Avatar

    you are so awesome

  6. Afif Iszuddin Avatar

    wow.. your explain make me understand so well.. thanks yaa

  7. Faisal Khan Avatar

    Network ip : 19 . 244 . 47 . 96
    usable host: 30

  8. Jacky Jiang Avatar

    number of usable hosts:30
    usable hosts:19.244.47.96~19.244.47.125
    am i right?

  9. TRAN NGOC NAM Avatar

    my tutor took 3 weeks straight to explain subnetting, i couldnt even understand 50% of it, only 2 videos from Bucky and i already understand the basic of subnetting. MAD RESPECT!!!

  10. sayed mufez Avatar

    IP address: 00010011 11110100 00101111 01110110
    Subnet mask: 11111111 11111111 11111111 11100000
    Network ID : 00010011 11110100 00101111 01100000
    Network IP: 19 . 244 . 47 . 96
    Number of hosts: 32
    One for Network IP -1
    One for Broadcast IP-1
    Number of Usable hosts: 30
    Usable hosts: 19 . 244 . 47 . 97– 19 . 244 . 47 . 126

  11. Wolfy Wolf Avatar

    Network id: 00010011.11110100.00101111.01100000
    network ip: 19.244.47.96
    32 hosts.
    30 usable hosts

  12. shruti agarwal Avatar

    If I have a single zero in my subnet mask den it means 2^1 = 2 I.e., 2 computers not a single computer so why It can't make a network..?

  13. Marci124 Avatar

    If you want a way to reason about the values without actually calculating the full binary, this is the way I went:
    We're missing 31 to 255.255.255.255, meaning all 1s. If you know that the max value of all digits to the right of digit 2^n is equal to 2^n – 1, you'll know that the last 5 bits are zeroes. Why? Because 2^n – 1 = 31 solves to n = 5, meaning everything right of the 2^5 digit; that is, the sixth-to-last digit, is out of the picture.
    This also means we have 2^5 – 2 = 30 usable hosts, and also that we're dealing with an A.B.C.0 /27 subnet mask.
    We'll now have to subtract the value of the 5 LSB (least significant bits) from the byte with value 118.
    It becomes clear that bit 8 (2^7) is a zero in the number 118, because 2^7 is still 128, greater than 118.
    We try to make up 118 from bytes available to us. Lucky for us, the A.B.C.0 /27 subnet mask means that we only have two available, bits 7 (2^6 = 64) and 6 (2^5 = 32).
    So it becomes obvious that both have to have a value of 1 to make 118, meaning our fourth byte (octet) is 0110 0000 which is 96 in decimal.

  14. Azad Sadr Avatar

    good job bucky, i love the way you teach, way to go

  15. Nouamane Raji Avatar

    at the end you said network ip/31 means you have only one computer, well it's just 2-2(broadcast & network)= 0. anyway ^^ I started the whole videos since yesterday to refresh my memory, and I'm on my way to the lesson 40. Good Jooob ! love your vids

  16. Patrascu Lucian Avatar

    We want more "homeworks" like this. For me it was a challenge. Having fun while solving it and helped with sticking this lesson into my head

  17. Patrascu Lucian Avatar

    1:08 – i don't need to explain how to convert to binary because we went over it in 2009

  18. Dan M Avatar

    Who would use a public IP from which to extract tens of other public ip's to assign hosts or it's just an example in how to find out a network address? Why you didn't used private ip' s for the tutorial?

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